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x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}
\large f(x)={\Large\frac1{\sigma\sqrt{2\pi}}} \int_{\small-\infty}^xe^{-\small\frac{(t-\mu)^2}{2\sigma^2}}dt
={\Large\frac1{\sigma\sqrt{2\pi}}} \int_{\small-\infty}^xe^{-\small\frac{(t-\mu)^2}{2\sigma^2}}dt)
x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}
\large f(x)={\Large\frac1{\sigma\sqrt{2\pi}}} \int_{\small-\infty}^xe^{-\small\frac{(t-\mu)^2}{2\sigma^2}}dt
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